2q^2-4q-1=7q^2-7q+1

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Solution for 2q^2-4q-1=7q^2-7q+1 equation: 



2q^2-4q-1=7q^2-7q+1

We move all terms to the left:

2q^2-4q-1-(7q^2-7q+1)=0

We get rid of parentheses

2q^2-7q^2-4q+7q-1-1=0

We add all the numbers together, and all the variables

-5q^2+3q-2=0

a = -5; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·(-5)·(-2)
Δ = -31
Delta is less than zero, so there is no solution for the equation

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